x^2+98x+720=0

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Solution for x^2+98x+720=0 equation:



x^2+98x+720=0
a = 1; b = 98; c = +720;
Δ = b2-4ac
Δ = 982-4·1·720
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-82}{2*1}=\frac{-180}{2} =-90 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+82}{2*1}=\frac{-16}{2} =-8 $

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